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PHYSICS 2015 WAEC EXPO RUNZ




PHYSIC OBJ:
1-10: AACCCAABDC
11-20: BABAADAADD
21-30: DAAABBACDC
31-40: CDBDBACCAA
41-50: CCBADCCABD

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PHYSICS EXPO

(1a)
Projectile is a body undergoing a motion under the combined effect of horizontal and vertical forces

(1b)
The horizontal components of the velocity remains the same because the body undergoes a uniform motion

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(2)
Angle of projection(tita)=30degrees

velocity(u)=150m/s

At greatest height, v=0

t=Usin*tita/g

t=(150*sin30degrees)/10

=150*0.5/10

t=7.5s
=================================

(3)
Given original lenght(Lo)=2.00m

radius(r)=1.0mm=1*10^-3m

Extension(e)=25mm=2*10^-3m

Force(f)=10^3N

stress =force/area

Area(a)pie*R^2

=22/7*(10^-3)^2

3.142*10^16m^2

Stress=10^3/3.142*10^-6

=3.18*10^-1*10^3*10^6

=3.18*10^8Nm^-2

Strain=Extension/original length

=25*10^-3/2

=1.25*10^-2

Young modulus(Y)=3.18*10^8/1.25*10^-2

Y-2.54*10^10Nm^-2
=================================

(4)
-By wind
-By increasing the cup surface area
-By reducing the temperature
===================================

(7a)
De brogile equation states that

landa=h/mv

where landa=wavelenght of light

mv=p=momentum

h=planck\'s constant

(7b)
The equation is used to explain the wave-nature of matter

==============================

(8ai)
Uniform acceleration occurs when there is an equal changein n velocity with equal time interval no matter how small the time interval may be

(8aii)
V=wr
V=linear velocity
w=angular velocity
r=radius

(8b)
R= resultant
R=root(F1^2+F2^2)
R=root(30^2+40^2)
R=root(2500)
R=50N

(8c)
This is done to increase the surface friction in water

(8di)
Given;mass(m)=20kg
angle of inclineation(tita)=30degrees
F=UR
F=Umgcos*tita
ma*sin*tita=Umg cos tita
U=tan*tita
U=tan30
U=0.51

(8dii)
Frictional force(Fr)
Fr=Umgcos*tita
Fr=0.51*20*10*c0s30
Fr=90.9N


(10ai)
Resonance ia a phenomenon whereby a vibrating body sets another bodies vibrating all oscillating at d same neutal frequency

(10aii)
(1)Radio-recieving circuit
(2)Sets of bob of pendulum

(10aiii)
Loudness is the sensation of sound reaching d ear while intensity is d ratio of d power to d area

(10b)
Wavelenght & speed

(10d)
Given; focal lenght(f)=18.0m
Object distance(u)=90.0m
Image height(hi)=1.0m

(10di)
1/u+1/v=1/f
1/90+1/v=-1/18
1/v=-1/18-1/90
1/v=(-5-1)/90
1/v=-6/90
v=-90/6
=-15cm

(10dii)
v/u=hi/ho
15/90=1.0/h0
ho=90/15
=6cm
Lenght of shark is 6cm

(12a)
Nucleon number is the sum of proton number and neutron number

(12b)
95=c+a
95=c+2
c=95-2
c=93

(12bi)
Number of neutrons in americium-241 is
237-93=144

(12ii)
a=2, b=4, c=93

(12ci)
Gamma ray is not deflected because it has no charge

(12cii)
-It has the highest penetrating power
-it has low ionizing power

(12d)
N/Nt=(1/2)^t1/2/T
1/32=(1/2)^(110/t1/2)
5=110/t1/2
5t1/2=110
t1/2=110/5
t1/2=22s
t1/2=0.693/landa
22=0.693/landa
landa=0.693/22
landa=0.0315
landa=0.0315 per year

PHYSIC OBJ:
1-10: AACCCAABDC
11-20: BABAADAADD
21-30: DAAABBACDC
31-40: CDBDBACCAA
41-50: CCBADCCABD


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